is there a macro available that will convert lists of urls like

http://www.abc.com/widgets/1.html
http://www.abc.com/widgets/2.html
http://www.abc.com/widgets/3.html
..
http://www.abc.com/widgets/99.html

to
<a href="http://www.abc.com/widgets/1.html">http://www.abc.com/widgets/1.html</a>
<a href="http://www.abc.com/widgets/2.html">http://www.abc.com/widgets/2.html</a>
<a href="http://www.abc.com/widgets/2.html">http://www.abc.com/widgets/3.html</a>
<a href="http://www.abc.com/widgets/3.html">http://www.abc.com/widgets/4.html</a>

That's not really a job for a macro, more for a regular expression. Take note of this article that explains the difficulty in solving this problem, though: Detecting URLs in a block of text

In your case, I would recommend a Perl regular expression replace action as follows:

Search string:

\b((https?|ftp|file)://[-A-Z0-9+&@#/%?=~_|!:,.;]*[A-Z0-9+&@#/%=~_|])

Replace all with

<a href="\1">\1</a>

This will only find URLs that start with http(s)/ftp/file, not "simplified" URLs that start with www; it also won't find URLs that end in parentheses and some other corner cases. This is just a starting point, so if this works for your real-life data, fine. If not, check out the article linked above whether you need a different pattern.

Thank you kindly. This is awesome.